Solving CVRP with ACO

Minimizing Travel Cost for Complex Delivery Problems

Start With The Story

This scenario involves the Capacitated Vehicle Routing Problem, solved using the meta-heuristics algorithm Ant Colony Optimization. Basically, VRP is a network consisting of a number of nodes (sometimes called cities) and arcs connecting one to all others along with the corresponding costs. Mostly, the aim is to minimize the cost in visiting each customer once and only once. The term "capacitated" is added due to some capacity constraints on the vehicles (vcap).

Enter the problem. Some company wants to deliver loads to a number of customers. In this case, we have 24 nodes based on the location of Germany's train stations (don't ask why). The delivery always starts from and ends at the depot, visiting a list of customers in other cities. And then a number of questions arise:

  • How do we minimize the travel cost in terms of distance?
  • How many trucks are required?
  • Which cities are visited by the truck #1, #2. etc.?
Such questions are addressed by employing the ants.

How to use this page?
Two parameters can be adjusted:
  • depot: [0..23], def = 0
  • vcap: [200..400], def = 400
Calling this page without parameter will get the defaults. Otherwise, just try something like this

There is a way to set all the demands, but I don't think you are ready for that. 😉
Map
DEPOT: Berlin Hbf
VCAP: 300 vol.
ACTIVE: 22 customers
  1. Kassel-Wilhelmshöhe (95 vol.)
  2. Düsseldorf Hbf (60 vol.)
  3. Frankfurt Hbf (45 vol.)
  4. Hannover Hbf (75 vol.)
  5. Aachen Hbf (30 vol.)
  6. Dresden Hbf (50 vol.)
  7. Hamburg Hbf (90 vol.)
  8. München Hbf (35 vol.)
  9. Bremen Hbf (50 vol.)
  10. Leipzig Hbf (80 vol.)
  11. Dortmund Hbf (55 vol.)
  12. Nürnberg Hbf (80 vol.)
  13. Karlsruhe Hbf (95 vol.)
  14. Ulm Hbf (35 vol.)
  15. Köln Hbf (100 vol.)
  16. Mannheim Hbf (100 vol.)
  17. Kiel Hbf (30 vol.)
  18. Mainz Hbf (85 vol.)
  19. Würzburg Hbf (65 vol.)
  20. Saarbrücken Hbf (60 vol.)
  21. Osnabrück Hbf (85 vol.)
  22. Freiburg Hbf (80 vol.)
Result
OVERALL | #TOURS: 5 | COST: 7560.772 km | LOAD: 1480 vol. | VCAP: 300 vol.
Tour 1
COST: 1252.129 km
LOAD: 285 vol.

  1. Dresden Hbf | 50 vol.
  2. Leipzig Hbf | 80 vol.
  3. Hannover Hbf | 75 vol.
  4. Bremen Hbf | 50 vol.
  5. Kiel Hbf | 30 vol.

Tour 2
COST: 1219.43 km
LOAD: 300 vol.

  1. Dortmund Hbf | 55 vol.
  2. Düsseldorf Hbf | 60 vol.
  3. Köln Hbf | 100 vol.
  4. Osnabrück Hbf | 85 vol.

Tour 3
COST: 1407.318 km
LOAD: 295 vol.

  1. Hamburg Hbf | 90 vol.
  2. Kassel-Wilhelmshöhe | 95 vol.
  3. Frankfurt Hbf | 45 vol.
  4. Würzburg Hbf | 65 vol.

Tour 4
COST: 1825.184 km
LOAD: 300 vol.

  1. Aachen Hbf | 30 vol.
  2. Saarbrücken Hbf | 60 vol.
  3. Karlsruhe Hbf | 95 vol.
  4. Ulm Hbf | 35 vol.
  5. Nürnberg Hbf | 80 vol.

Tour 5
COST: 1856.711 km
LOAD: 300 vol.

  1. Mainz Hbf | 85 vol.
  2. Mannheim Hbf | 100 vol.
  3. Freiburg Hbf | 80 vol.
  4. München Hbf | 35 vol.

ANTS
#generations: 10 for global, 5 for local
#ants: 5 times #active_customers

ACO
Rel. importance of pheromones α = 1.0
Rel. importance of visibility β = 10.0
Trail persistance ρ = 0.5
Pheromone intensity Q = 10

See this wikipedia page to learn more.

What kind of cost?
Directed driving distance, obtained through Google API. The visualization does not display that since the idea is VRP. Adding such feature is very easy, but not a priority for this case.
Can we use any address?
Yes, absolutely. What we need is the geo-coordinates of the addresses, and the distance matrix, which is not a problem. See my oldie master thesis here, implemented using PHP/MySQL for a delivery case in Darmstadt city, Germany.
Travel time as the cost?
Just replace the distance matrix with a duration matrix, then it is done. Please keep in mind, this feature is not intended for realtime use. But regarding the idea, not an issue.
Up to how many nodes?
There is no definitive answer for that. However, if a large number of nodes involved, a good strategy is required. Actually, for this one, a suitable technique is already implemented instead of a "plain" ACO. 

NETWORK
Depo: [1] Berlin Hbf | Number of cities: 24 | Total loads: 1480 vol. | Vehicle capacity: 300 vol.
Loads: [95, 0, 60, 45, 75, 30, 0, 50, 90, 35, 50, 80, 55, 80, 95, 35, 100, 100, 30, 85, 65, 60, 85, 80]

ITERATION
Generation: #1
Best cost: 9681.507 | Path: [1, 0, 12, 2, 5, 3, 1, 11, 7, 13, 20, 1, 8, 18, 4, 10, 9, 1, 22, 16, 19, 1, 17, 14, 15, 21, 1, 23, 1]
Best cost: 8772.916 | Path: [1, 2, 16, 5, 12, 10, 1, 7, 11, 4, 8, 1, 18, 22, 0, 20, 1, 13, 9, 15, 14, 3, 1, 17, 19, 21, 1, 23, 1]
Best cost: 8756.820 | Path: [1, 3, 19, 17, 21, 1, 11, 7, 20, 13, 1, 4, 10, 22, 12, 5, 1, 8, 18, 0, 2, 1, 23, 14, 15, 9, 1, 16, 1]
Best cost: 8502.268 | Path: [1, 5, 16, 2, 12, 10, 1, 11, 7, 13, 20, 1, 22, 4, 8, 18, 1, 0, 3, 19, 21, 1, 9, 15, 14, 17, 1, 23, 1]
Best cost: 7793.058 | Path: [1, 11, 7, 4, 10, 18, 1, 22, 12, 2, 16, 1, 8, 0, 3, 20, 1, 13, 15, 14, 21, 5, 1, 17, 19, 23, 9, 1]

OPTIMIZING each tour...
Current: [[1, 11, 7, 4, 10, 18, 1], [1, 22, 12, 2, 16, 1], [1, 8, 0, 3, 20, 1], [1, 13, 15, 14, 21, 5, 1], [1, 17, 19, 23, 9, 1]]
[1] Cost: 1351.325 to 1252.129 | Optimized: [1, 7, 11, 4, 10, 18, 1]
[2] Cost: 1226.259 to 1219.430 | Optimized: [1, 12, 2, 16, 22, 1]
[4] Cost: 1828.055 to 1825.184 | Optimized: [1, 5, 21, 14, 15, 13, 1]
[5] Cost: 1980.101 to 1856.711 | Optimized: [1, 19, 17, 23, 9, 1]

ACO RESULTS
[1/285 vol./1252.129 km] Berlin Hbf -> Dresden Hbf -> Leipzig Hbf -> Hannover Hbf -> Bremen Hbf -> Kiel Hbf --> Berlin Hbf
[2/300 vol./1219.430 km] Berlin Hbf -> Dortmund Hbf -> Düsseldorf Hbf -> Köln Hbf -> Osnabrück Hbf --> Berlin Hbf
[3/295 vol./1407.318 km] Berlin Hbf -> Hamburg Hbf -> Kassel-Wilhelmshöhe -> Frankfurt Hbf -> Würzburg Hbf --> Berlin Hbf
[4/300 vol./1825.184 km] Berlin Hbf -> Aachen Hbf -> Saarbrücken Hbf -> Karlsruhe Hbf -> Ulm Hbf -> Nürnberg Hbf --> Berlin Hbf
[5/300 vol./1856.711 km] Berlin Hbf -> Mainz Hbf -> Mannheim Hbf -> Freiburg Hbf -> München Hbf --> Berlin Hbf
OPTIMIZATION RESULT: 5 tours | 7560.772 km.